# Level03

Using hexrays, we can decompile the code and see that it `decrypt()`s a constant string (`"Q}|u`sfg~sf{}|a3"` with a key that we can input (more or less).
Basically, the code will `xor` each character of the string with the key.
The modified string will then be compared to `"Congratulations!"` and execute a shell if the value matches.
All we have to do is find the key where `'Q'^key == 'C'`. We use this (xor calculator)[https://xor.pw/] to find the value, which is 18 in decimal.
Finally, we need to input this through the `scanf()` call. This will store our input in a variable that will then be passed as the first parameter of the `test()` function.
The second parameter is `322424845` and `test()` will call `decrypt()` with the difference between `a2` and `a1` (let's call it `key`).
Since `a2 == 322424845` and we want `key == 18`, we need to have `a1 == a2 - 18`, which is `322424827`.
We just need to input this value into the program.

Here is the command:
`(echo 322424827; cat) | ./level03`
