11 lines
778 B
Plaintext
11 lines
778 B
Plaintext
# Level6
|
|
|
|
Using ghidra, we can decompile the code and see that it calls `malloc()` twice.
|
|
The first malloc has a size of 64 bytes and is a buffer where the program will `strcpy(buf, av[1])`. The second one is a function pointer pointing to `m()` printing `"Nope."`. We want to change its value to point to the correct function `n()` that will open a shell.
|
|
To achieve this, we will overflow the first malloc and the second one's header so that we can write the adress through the input in `av[1]`.
|
|
To calculate the offset between the 2 allocations, we used gdb's breakpoints and prints, leading us to an offset of 72 bytes (64 + 8).
|
|
We just need to print 72 bytes followed by the address of `n()`.
|
|
|
|
Here is the command:
|
|
./level6 $(python -c 'print "A"*72 + "\x54\x84\x04\x08"')
|