fix: bunch of improvements and typos in the walkthrough
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@ -1,9 +1,10 @@
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# Level6
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Using ghidra, we can decompile the code and see that it calls `malloc` twice.
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The first malloc has a size of 64 bytes and is a buffer where the program will `strcpy(buf, av[1])`. The second one is a function pointer pointing to `m()` function by default (prints "Nope."). We want to change its value to point to the correct function `n()` that will open a shell.
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Using ghidra, we can decompile the code and see that it calls `malloc()` twice.
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The first malloc has a size of 64 bytes and is a buffer where the program will `strcpy(buf, av[1])`. The second one is a function pointer pointing to `m()` printing `"Nope."`. We want to change its value to point to the correct function `n()` that will open a shell.
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To achieve this, we will overflow the first malloc and the second one's header so that we can write the adress through the input in `av[1]`.
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To calculate the offset between the 2 allocations, we used gdb's breakpoints and prints, leading us to an offset of 72 bytes (64 + 8).
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We just need to print 72 bytes followed by the address of `n()`.
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Here is the command:
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./level6 $(python -c 'print "A"*72 + "\x54\x84\x04\x08"')
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